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                                Wayne Goode 10.22.2009

                                  • String.Format refactoring produces incorrect result.

                                    Steps to Reproduce:

                                    Module Module1

                                        Sub Main()

                                            Dim a, b As Double

                                            Dim s As String

                                            ' apply "Use String.Format" refactoring

                                            s = a & " " & a / b

                                        End Sub

                                    End Module

                                    Actual Results:

                                    s = String.Format("{0} {0}{1}", a, b)

                                    Expected Results:

                                    s = String.Format("{0} {1}", a, a / b)

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